CodeForces 514A – Chewbaсca and Number

闲的蛋疼,前两个月学了java,今天又学了Python,所以找了个水题,熟悉一下四种语言。

其实语言不是问题,思路有了,换个语言,如果基本语法会的话,根本不成问题。

确实,Python就是够简洁。因为java和Python只知道点皮毛,可能写的还不够好。

Description

Luke Skywalker gave Chewbacca an integer number x. Chewbacca isn’t good at numbers but he loves inverting digits in them. Inverting digit tmeans replacing it with digit 9 - t.

Help Chewbacca to transform the initial number x to the minimum possible positive number by inverting some (possibly, zero) digits. The decimal representation of the final number shouldn’t start with a zero.

Input

The first line contains a single integer x(1 ≤ x ≤ 1018) — the number that Luke Skywalker gave to Chewbacca.

Output

Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn’t contain leading zeroes.

Sample Input

Input
27
Output
22
Input
4545
Output
4444

ANSI C:

#include <string.h>
#include <stdio.h>

void change(char *x){
    *x =  '0' + 9 - *x + '0';
}
int main()
{
    char num[32];
    scanf("%s", num);
    if(num[0]!='9' && num[0]>='5')
        change(&num[0]);
    int i;
    for(i = 1; i < strlen(num); ++i)
        if(num[i]>='5')
            change(&num[i]);
    puts(num);
    return 0;
}

C++:

#include <iostream>
#include <cstring>
#include <cstdlib>
#include <cctype>

using namespace std;

inline void change(char & x){
    x =  '0' + 9 - x + '0';
}
int main()
{
    char num[32];
    cin >> num;
    if(num[0]!='9' && num[0]>='5')
        change(num[0]);
    for(int i = 1; i < strlen(num); ++i)
        if(num[i]>='5')
            change(num[i]);
    cout << num << endl;
    return 0;
}

Java:

import java.util.*;

public class Main {
	public static void main(String[] args) {
		Scanner cin = new Scanner(System.in);
		String num = cin.next();
		for(int i = 0; i < num.length(); ++i){
			if(i==0){
				if('5' <= num.charAt(0) && num.charAt(0) <= '8')
					System.out.print((char)('0' + 9 - num.charAt(0) + '0'));
				else
					System.out.print(num.charAt(0));
			}
			else{
				if('5' <= num.charAt(i) && num.charAt(i) <= '9')
					System.out.print((char)('0' + 9 - num.charAt(i) + '0'));
				else
					System.out.print(num.charAt(i));
			}
		}
		cin.close();
	}

}

Python:

x = list(input())
for i in range(len(x)):
    if (i == 0 and '5' <= x[0] <= '8') or (i != 0 and '5' <= x[i] <= '9'):
        x[i] = str(9-int(x[i]))
    print(x[i], end = '')

看看最后的代码量和运行时间吧:

QQ截图20150216222533